12x^2+12x-7=0

Solution for 12x^2+12x-7=0 equation:

12x^2+12x-7=0

a = 12; b = 12; c = -7;
Δ = b2-4ac
Δ = 122-4·12·(-7)
Δ = 480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{480}=\sqrt{16*30}=\sqrt{16}*\sqrt{30}=4\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{30}}{2*12}=\frac{-12-4\sqrt{30}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{30}}{2*12}=\frac{-12+4\sqrt{30}}{24}
$